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android – How do I access the views inside the layout when I reuse it multiple times?

Posted by: admin April 23, 2020 Leave a comment

Questions:

I have read the Android UI trick 2 on Android developers, which tells people how to include a layout in another layout file multiple times, and give these included layouts different id. However, the sample here is overwriting the layout id, not the id of the views IN this layout. For example, if the workspace_screen.xml looks like this:

<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:orientation="vertical">
<TextView android:id="@+id/firstText"
    android:layout_width="fill_parent"
    android:layout_height="wrap_content"
    android:text="first"/>
<TextView android:id="@+id/secondText"
    android:layout_width="fill_parent"
    android:layout_height="wrap_content"
    android:text="second"/>

And I include it three times in another layout file. Do I end up with three TextViews with id firstText, and another three with secondText? Isn’t there an id collision? And how do I find the secondText TextView in the third included layout with findViewById? What should I input in the findViewById method?

How to&Answers:

Say you want to include this:

<LinearLayout
    android:layout_height="wrap_content"
    android:layout_width="fill_parent"
    android:orientation="horizontal"
>
    <ImageView
        android:layout_height="wrap_content"
        android:layout_width="wrap_content"
        android:src="@drawable/some_image"
    />
    <TextView
        android:id="@+id/included_text_view"
        android:layout_height="wrap_content"
        android:layout_width="wrap_content"
    />
</LinearLayout>

so in your code you insert it like this:

<LinearLayout
    android:layout_height="wrap_content"
    android:layout_width="fill_parent"
    android:orientation="vertical"
>
    <include android:id="@+id/header_1" layout="@layout/name_of_layout_xml" />
    <include android:id="@+id/header_2" layout="@layout/name_of_layout_xml" />
</LinearLayout>

now you want to access the text views within the included layouts to set the text dynamically. In your code you simply type:

LinearLayout ll = (LinearLayout)findViewById(R.id.header_1);
TextView tv = (TextView)ll.findViewById(R.id.included_text_view);
tv.setText("Header Text 1");

ll = (LinearLayout)findViewById(R.id.header_2);
tv = (TextView)ll.findViewById(R.id.included_text_view);
tv.setText("Header Text 2");

notice that you use the individual LinearLayouts’ findViewById methods to narrow the search to only their children.

Answer:

I wanted to create TableRow layout and wanted to reuse it to my code in for loop. I was searching for the problem and at last found solution.

        TableLayout table = (TableLayout) findViewById(R.id.listTable);
        LayoutInflater inflater = (LayoutInflater) getSystemService(Context.LAYOUT_INFLATER_SERVICE);
        ImageButton[] button = new ImageButton[4];
        TableRow[] row = new TableRow[4];

        for(int i =0 ; i<4;i++){

                row[i] = (TableRow) inflater.inflate(R.layout.list_row, null);
                table.addView(row[i]);
                button[i] = (ImageButton)row[i].findViewById(R.id.editBtn);
                button[i].setOnClickListener(new OnClickListener() {

                    @Override
                    public void onClick(View v) {
                        // TODO Auto-generated method stub
                        Log.i(TAG,"Button Clicked");
                    }
                });

This way you can achieve the functionality of reusing the layout and also can access inner elements