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Android: How to find the position clicked from the context menu

Posted by: admin April 23, 2020 Leave a comment

Questions:

I have a list view filled with data. I set up a context menu for the listview using the following code:

list.setOnCreateContextMenuListener
(
  new View.OnCreateContextMenuListener() 
  {
        public void onCreateContextMenu(ContextMenu menu, View view, ContextMenu.ContextMenuInfo menuInfo) 
        {
       AdapterContextMenuInfo mi =(AdapterContextMenuInfo) menuInfo;
       menu.add(0, 0, 0, "Delete item");                
    }
   }
);

I have the following method override to control de contextmenu menuitem selected:

@Override
public boolean onContextItemSelected(MenuItem item) 
{
  switch(item.getItemId()) 
  { 
  case 0: 
    ShowAlert("hello from delete item");
    break; 
  default: 
  return super.onContextItemSelected(item); 
  } 
  return true; 
}

In this overrided method, how could i find the item of the list view that was clicked?

Thanks in advance.
Best Regards.
Jose

How to&Answers:

You can use the ContextMenu.ContextMenuInfo.

Something like that:

@Override
public boolean onContextItemSelected(MenuItem item) {
    AdapterContextMenuInfo info = (AdapterContextMenuInfo) item.getMenuInfo();
    int index = info.position;
}

You can also get the exact View for which the menu is being displayed:

@Override
public boolean onContextItemSelected(MenuItem item) {
    AdapterContextMenuInfo info = (AdapterContextMenuInfo) item.getMenuInfo();
    int index = info.position;
    View view = info.targetView;
}

Answer:

private static final int EDIT_ID = Menu.FIRST + 3;
private static final int DELETE_ID = Menu.FIRST + 4;
 @Override
    public void onCreateContextMenu(ContextMenu menu, View v,
            ContextMenu.ContextMenuInfo menuInfo) {
        menu.add(Menu.NONE, EDIT_ID, Menu.NONE, "Edit").setAlphabeticShortcut(
                'e');
        menu.add(Menu.NONE, DELETE_ID, Menu.NONE, "Delete")
                .setAlphabeticShortcut('d');
    }

    @Override
    public boolean onContextItemSelected(MenuItem item) {
        AdapterView.AdapterContextMenuInfo info = (AdapterView.AdapterContextMenuInfo) item
                .getMenuInfo();
        switch (item.getItemId()) {
        case EDIT_ID:

            edit(info.id);
            return (true);
        case DELETE_ID:

            delete(info.id);
            return (true);
        }

        return (super.onOptionsItemSelected(item));
    }

Answer:

OK, to solve problem info null ****
use static member and set value from Position of your holder
to save the value in longclick method member for example:-

public class CurrentPosition {
   public static  int Pos{ get; set; }
}

public bool OnLongClick(View v)
{
    CurrentPosition.Pos = Position;
    return false;
}

and use in your context select item:

public override bool OnContextItemSelected(IMenuItem item)
{
    switch (item.ItemId)
    {
        case 0:
            return true;
        case 1:
            Toast.MakeText(this,CurrentPosition.Pos.ToString(), ToastLength.Long).Show();
            return true;
        case 2:
            Toast.MakeText(this, "Save", ToastLength.Long).Show();
            return true;
        }
        return true;
    }
}

C# code