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android – Property must be initialized or be abstract

Posted by: admin March 11, 2020 Leave a comment

Questions:

It must be stupid question, but I’m really new to Kotlin and I didn’t find any solution.

How to declare class field? Like we can have it in java:

protected SharedPreferences mSharedPreferences;

And later in onCreate():

mSharedPreferences = PreferenceManager.getDefaultSharedPreferences(this)

Now I can use it anywhere I want (in subclasses of this base activity).

I try to do same in Kotlin:

protected var sharedPreferences : SharedPreferences

And in onCreate():

sharedPreferences = PreferenceManager.getDefaultSharedPreferences(this)

But I get a warning: “Property must be initialized or be abstract”

How to&Answers:

If you’d like to initialize a property outside the constructor, then late-initialized properties is what you may be looking for. Declare the property with the lateinit modifier, which will allow to skip the otherwise required initializer and will make the property access fail with exception until some meaningful value is assigned to it:

protected lateinit var sharedPreferences: SharedPreferences

Answer:

Pulling this out of the comments from Alexander Udalov’s answer for visibility.
For nullable properties:

protected var sharedPreferences : SharedPreferences? = null

…and assign it a value later.