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Convert a Python list with strings all to lowercase or uppercase

Posted by: admin November 1, 2017 Leave a comment

Questions:

I have a python list variable that contains strings. Is there a python function that can convert all the strings in one pass to lowercase and vice versa, uppercase?

Answers:

It can be done with list comprehensions

>>> [x.lower() for x in ["A","B","C"]]
['a', 'b', 'c']
>>> [x.upper() for x in ["a","b","c"]]
['A', 'B', 'C']

or with map function

>>> map(lambda x:x.lower(),["A","B","C"])
['a', 'b', 'c']
>>> map(lambda x:x.upper(),["a","b","c"])
['A', 'B', 'C']

Questions:
Answers:

Besides being easier to read (for many people), list comprehensions win the speed race, too:

$ python2.6 -m timeit '[x.lower() for x in ["A","B","C"]]'
1000000 loops, best of 3: 1.03 usec per loop
$ python2.6 -m timeit '[x.upper() for x in ["a","b","c"]]'
1000000 loops, best of 3: 1.04 usec per loop

$ python2.6 -m timeit 'map(str.lower,["A","B","C"])'
1000000 loops, best of 3: 1.44 usec per loop
$ python2.6 -m timeit 'map(str.upper,["a","b","c"])'
1000000 loops, best of 3: 1.44 usec per loop

$ python2.6 -m timeit 'map(lambda x:x.lower(),["A","B","C"])'
1000000 loops, best of 3: 1.87 usec per loop
$ python2.6 -m timeit 'map(lambda x:x.upper(),["a","b","c"])'
1000000 loops, best of 3: 1.87 usec per loop

Questions:
Answers:
>>> map(str.lower,["A","B","C"])
['a', 'b', 'c']

Questions:
Answers:

List comprehensions is how I’d do it. This snippet below shows how to convert a list to all upper case then back to lower:

$ python
Python 2.5.2 (r252:60911, Dec  2 2008, 09:26:14)
[GCC 3.4.4 (cygming special, gdc 0.12, using dmd 0.125)] on cygwin
Type "help", "copyright", "credits" or "license" for more information.

>>> list = ["one", "two", "three"]
>>> list
['one', 'two', 'three']

>>> list = [element.upper() for element in list]
>>> list
['ONE', 'TWO', 'THREE']

>>> list = [element.lower() for element in list]
>>> list
['one', 'two', 'three']

Questions:
Answers:

For this sample the comprehension is fastest

$ python -m timeit -s 's=["one","two","three"]*1000' '[x.upper for x in s]'
1000 loops, best of 3: 809 usec per loop

$ python -m timeit -s 's=["one","two","three"]*1000' 'map(str.upper,s)'
1000 loops, best of 3: 1.12 msec per loop

$ python -m timeit -s 's=["one","two","three"]*1000' 'map(lambda x:x.upper(),s)'
1000 loops, best of 3: 1.77 msec per loop

Questions:
Answers:
mylist = ['Mixed Case One', 'Mixed Case Two', 'Mixed Three']
print map(lambda x: x.lower(), mylist)
print map(lambda x: x.upper(), mylist)

Questions:
Answers:

a student asking, another student with the same problem answering :))

fruits=['orange', 'grape', 'kiwi', 'apple', 'mango', 'fig', 'lemon']
newList = []
for fruit in fruits:
    newList.append(fruit.upper())
print(newlist)