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Excel help on combination of Index – match and sumifs?

Posted by: admin May 14, 2020 Leave a comment


I have these three tables as shown in this image below:
SalesOrderTable, OrderAdjustmentTable, and TotalSalesTable.

enter image description here


Each order number in the SalesOrderTable represent an order number for a product from the same invoice. It has A,B, or C if an invoice is made for more than one product, but not if it is only made for one product.
E.g.: Order 1703 has two products, so it has A and B at the end of each order number. Order 1704 has an order for Apple only, so it doesn’t have any letter at its end.


Should there be any adjustments for each order number, they are inputted manually in the adjustment columns.


In this table, all amount of total sales and adjustments for the same order number are totaled. So order for 1705 are combinations of 1705A, 1705B, 1705C.

Here are my current formulas, all of them produce error messages or don’t calculate correctly.

Order total amount column:

=SUMIF(SalesOrderTable[Order Number], LEFT(G4,LEN(SalesOrderTable[Order Number])-1),SalesOrderTable[Order Sales Amount])

Order Total Adjustment Column:

=sumifs(OrderAdjustmentTable[#All],OrderAdjustmentTable[Order Number],MATCH(B19,LEFT(SalesOrderTable[Order Number],LEN(SalesOrderTable[Order Number])-1), 0), "*Adjustment",OrderAdjustmentTable[#All])

I know it may have something to do with match and sumifs, but all the formulas I made led to error messages.
Anybody can help me with what I did wrong with these formulas above, and how do I fix them? I am at my wits end here and will appreciate any advice given. Thanks a lot!


What I want to achieve is to fill:

The order total amount column in TotalSalesTable with all orders that have the same order number, irrespective of their ABC. So Total amount for 1705 will be the sum total of order amount for 1705A, 1705B, 1705C.

For the order total adjustment, I want to have all the adjustments value for the order number column in TotalSalesTable from OrderAdjustmentTable, irrespective of their ABC. So total adjustments for 1705 in TotalSalesTable will be 1705B and 1705C.

How to&Answers:

As long as there are no orders that overlap with and without letters (for instance, the SalesOrderTable having records for 1703, 1703A, and 1703B), the following formula should work in cell C19, from where you can copy it down:

Order Total Amount:

=SUMIFS(SalesOrderTable[Order Sales Amount],SalesOrderTable[Order Number],$B19)+SUMIFS(SalesOrderTable[Order Sales Amount],SalesOrderTable[Order Number],$B19&"*")

This formula adds together the exact and approximate matches, but like I said if any orders both have and are lacking a letter something will likely get duplicated/double counted. You should also be able to replicate the formula for the Order Total Adjustment Column.


In messing around with this for a second, putting LEFT in SUMIF seems to cause issues (at least on Mac).

I’d recommend calculating Order Number without the letters in a separate column first. LEFT returns a character string so I had to wrap it in VALUE so that SUMIF will match. Since all of yours are four digits, I just used VALUE(LEFT([@[Order Number]],4))

Then it’s just standard SUMIF notation:

=SUMIF(Table1[Base Num],[@[Order Number]],Table1[Order Sales Amount])

Example: https://www.dropbox.com/s/yj6ktl14jqglxsm/Example.xlsx?dl=0

There are various ways you could get the order number, but you have to be careful with your example:

LEFT(G4,LEN(SalesOrderTable[Order Number])-1) because this will work correctly for 1703A and 12990B, but will drop a number from 1701.

EDIT: This is one way to get order number if your number of digits varies: =IFERROR(VALUE(A2),VALUE(LEFT(A2,LEN(A2)-1)))

This says, “if VALUE(A2) returns an error (meaning it has a letter in it), remove the last character, otherwise, use VALUE(A2) since it’s already a number.”