I have cells in columns A and B. I am interested in the cases in which neither the cell in column A nor its neighbour in column B is empty. (For example, when cells A12 and B12 both contain something.)

How can I count the number of times both cells in a pair are non-empty?

So far, I’ve had a column C, with each cell having `=IF(OR(ISBLANK(A2),ISBLANK(B2)), 0, 1)`

, `=IF(OR(ISBLANK(A3),ISBLANK(B3)), 0, 1)`

, etc. with a `SUM`

function at the bottom of Column C, but I am wondering if there is a more efficient way to count these.

COUNTIFS should do this handily.

```
=countifs(a:a, "<>", b:b, "<>")
```

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# SUMPRODUCT ‘Deals’ in Arrays 4

Calculates (counts) the number of rows where cells in column `A`

**AND** column `B`

, contain data.

`=SUMPRODUCT(--NOT(ISBLANK(A$1:A$5000)),--NOT(ISBLANK(B$1:B$5000)))`

Calculates (counts) the number of rows where cells in column `A`

**AND** column `B`

, are blank.

```
=SUMPRODUCT(--ISBLANK(A$1:A$5000),--ISBLANK(B$1:B$5000))
```

Would appreciate anyone’s feedback if the following formula is working and in which Excel version (not working in 2003):

```
=SUMPRODUCT(--NOT(ISBLANK(A:A)),--NOT(ISBLANK(B:B)))
```

Tags: excelexcel