I constantly use the website below to track air miles round trip. Recently, the website stopped working in IE, so my code did as well. Since I use this on a work computer, I cannot download many of the other solutions that I have found in my searches and I cannot use another website without going through a lengthy process to get the site approved. Is there a way to perform the same task here in Chrome without any other downloads?

```
Dim ele As Object
Dim IE As New InternetExplorer
IE.Visible = True
IE.navigate "http://www.distancefromto.net"
Do
DoEvents
Loop Until IE.readyState = READYSTATE_COMPLETE
'step 1
With IE
.document.getElementsByName("distance")(0).Value = Range("B2").Value
.document.getElementsByName("distance")(1).Value = Range("B3").Value & Range("E3").Value
.document.getElementById("hae").Click
Do
DoEvents
Loop Until IE.readyState = READYSTATE_COMPLETE
Application.Wait (Now + TimeValue("0:00:02"))
Dim a As String
a = Trim(.document.getElementById("totaldistancemiles").Value)
Dim aa As Variant
aa = Split(a, " ")
Range("C2").Value = aa(0)
'step 2
.document.getElementsByName("distance")(0).Value = Range("B4").Value & Range("E4").Value
.document.getElementById("hae").Click
Do
DoEvents
Loop Until IE.readyState = READYSTATE_COMPLETE
Application.Wait (Now + TimeValue("0:00:02"))
Dim b As String
b = Trim(.document.getElementById("totaldistancemiles").Value)
Dim bb As Variant
bb = Split(b, " ")
Range("C3").Value = bb(0)
'step 3
.document.getElementsByName("distance")(1).Value = Range("B2").Value
.document.getElementById("hae").Click
Do
DoEvents
Loop Until IE.readyState = READYSTATE_COMPLETE
Application.Wait (Now + TimeValue("0:00:02"))
Dim c As String
c = Trim(.document.getElementById("totaldistancemiles").Value)
Dim cc As Variant
cc = Split(c, " ")
Range("C4").Value = cc(0)
End With
IE.Quit
```

Any help, even a definitive “no, it’s not possible” would be greatly appriciated

Thanks

**Chrome:**

To use Chrome – no. You would need to download selenium basic or use a different programming language e.g python.

**Different site:**

You could switch to using a different site (appreciate there may some minor differences on your prior figures due to the website though technically the distances shouldn’t have changed that much!). I note you say that this would be problematic. At the risk of sounding stalkerish, you have used freemaptools before so that might be an acceptable choice?

**API:**

If you find a site offering an API service you might be able to ditch all the above and issue an XMLHTTP request. I couldn’t see your site offering an API service otherwise that would have been the obvious next choice.

@RahulChalwa mentions “[*the site OP is using is itself using a wrapper around google maps API: https://maps.googleapis.com/maps/api/js/GeocodeService.Search. User can register for API and do a POST request*]”; so that might be the way forward. Main documentation here.

E.g. API site: Personal and small scale use API – wheretocredit.com

**Current set-up debug:**

Ascertain the reason for IE no longer working in your current set-up would also be advisable, perhaps by contacting the site developers and raising your issue.

**Perform the calculation (as the site does) using the Vincenty’s formula or, as other sites do, using Haversine formula:**

Haversine:

Vicenty’s (including sample code):

How to Calculate Distance in Excel

Vicenty’s code from Contextures. I have attributed but if this should not be included here I will remove.

`'************************************************************* Private Const PI = 3.14159265358979 Private Const EPSILON As Double = 0.000000000001 Public Function distVincenty(ByVal lat1 As Double, ByVal lon1 As Double, _ ByVal lat2 As Double, ByVal lon2 As Double) As Double 'INPUTS: Latitude and Longitude of initial and ' destination points in decimal format. 'OUTPUT: Distance between the two points in Meters. ' '====================================== ' Calculate geodesic distance (in m) between two points specified by ' latitude/longitude (in numeric [decimal] degrees) ' using Vincenty inverse formula for ellipsoids '====================================== ' Code has been ported by lost_species from www.aliencoffee.co.uk to VBA ' from javascript published at: ' https://www.movable-type.co.uk/scripts/latlong-vincenty.html ' * from: Vincenty inverse formula - T Vincenty, "Direct and Inverse Solutions ' * of Geodesics on the Ellipsoid with application ' * of nested equations", Survey Review, vol XXII no 176, 1975 ' * https://www.ngs.noaa.gov/PUBS_LIB/inverse.pdf 'Additional Reference: https://en.wikipedia.org/wiki/Vincenty%27s_formulae '====================================== ' Copyright lost_species 2008 LGPL ' https://www.fsf.org/licensing/licenses/lgpl.html '====================================== ' Code modifications to prevent "Formula Too Complex" errors ' in Excel (2010) VBA implementation ' provided by Jerry Latham, Microsoft MVP Excel Group, 2005-2011 ' July 23 2011 '====================================== Dim low_a As Double Dim low_b As Double Dim f As Double Dim L As Double Dim U1 As Double Dim U2 As Double Dim sinU1 As Double Dim sinU2 As Double Dim cosU1 As Double Dim cosU2 As Double Dim lambda As Double Dim lambdaP As Double Dim iterLimit As Integer Dim sinLambda As Double Dim cosLambda As Double Dim sinSigma As Double Dim cosSigma As Double Dim sigma As Double Dim sinAlpha As Double Dim cosSqAlpha As Double Dim cos2SigmaM As Double Dim C As Double Dim uSq As Double Dim upper_A As Double Dim upper_B As Double Dim deltaSigma As Double Dim s As Double ' final result, will be returned rounded to 3 decimals (mm). 'added by JLatham to break up "Too Complex" formulas 'into pieces to properly calculate those formulas as noted below 'and to prevent overflow errors when using 'Excel 2010 x64 on Windows 7 x64 systems Dim P1 As Double ' used to calculate a portion of a complex formula Dim P2 As Double ' used to calculate a portion of a complex formula Dim P3 As Double ' used to calculate a portion of a complex formula 'See https://en.wikipedia.org/wiki/World_Geodetic_System 'for information on various Ellipsoid parameters for other standards. 'low_a and low_b in meters ' === GRS-80 === ' low_a = 6378137 ' low_b = 6356752.314245 ' f = 1 / 298.257223563 ' ' === Airy 1830 === Reported best accuracy for England and Northern Europe. ' low_a = 6377563.396 ' low_b = 6356256.910 ' f = 1 / 299.3249646 ' ' === International 1924 === ' low_a = 6378388 ' low_b = 6356911.946 ' f = 1 / 297 ' ' === Clarke Model 1880 === ' low_a = 6378249.145 ' low_b = 6356514.86955 ' f = 1 / 293.465 ' ' === GRS-67 === ' low_a = 6378160 ' low_b = 6356774.719 ' f = 1 / 298.247167 '=== WGS-84 Ellipsoid Parameters === low_a = 6378137 ' +/- 2m low_b = 6356752.3142 f = 1 / 298.257223563 '==================================== L = toRad(lon2 - lon1) U1 = Atn((1 - f) * Tan(toRad(lat1))) U2 = Atn((1 - f) * Tan(toRad(lat2))) sinU1 = Sin(U1) cosU1 = Cos(U1) sinU2 = Sin(U2) cosU2 = Cos(U2) lambda = L lambdaP = 2 * PI iterLimit = 100 ' can be set as low as 20 if desired. While (Abs(lambda - lambdaP) > EPSILON) And (iterLimit > 0) iterLimit = iterLimit - 1 sinLambda = Sin(lambda) cosLambda = Cos(lambda) sinSigma = Sqr(((cosU2 * sinLambda) ^ 2) + _ ((cosU1 * sinU2 - sinU1 * cosU2 * cosLambda) ^ 2)) If sinSigma = 0 Then distVincenty = 0 'co-incident points Exit Function End If cosSigma = sinU1 * sinU2 + cosU1 * cosU2 * cosLambda sigma = Atan2(cosSigma, sinSigma) sinAlpha = cosU1 * cosU2 * sinLambda / sinSigma cosSqAlpha = 1 - sinAlpha * sinAlpha If cosSqAlpha = 0 Then 'check for a divide by zero cos2SigmaM = 0 '2 points on the equator Else cos2SigmaM = cosSigma - 2 * sinU1 * sinU2 / cosSqAlpha End If C = f / 16 * cosSqAlpha * (4 + f * (4 - 3 * cosSqAlpha)) lambdaP = lambda 'the original calculation is "Too Complex" for Excel VBA to deal with 'so it is broken into segments to calculate without that issue 'the original implementation to calculate lambda 'lambda = L + (1 - C) * f * sinAlpha * _ (sigma + C * sinSigma * (cos2SigmaM + C * cosSigma * _ (-1 + 2 * (cos2SigmaM ^ 2)))) 'calculate portions P1 = -1 + 2 * (cos2SigmaM ^ 2) P2 = (sigma + C * sinSigma * (cos2SigmaM + C * cosSigma * P1)) 'complete the calculation lambda = L + (1 - C) * f * sinAlpha * P2 Wend If iterLimit < 1 Then MsgBox "iteration limit has been reached, something didn't work." Exit Function End If uSq = cosSqAlpha * (low_a ^ 2 - low_b ^ 2) / (low_b ^ 2) 'the original calculation is "Too Complex" for Excel VBA to deal with 'so it is broken into segments to calculate without that issue 'the original implementation to calculate upper_A 'upper_A = 1 + uSq / 16384 * (4096 + uSq * _ (-768 + uSq * (320 - 175 * uSq))) 'calculate one piece of the equation P1 = (4096 + uSq * (-768 + uSq * (320 - 175 * uSq))) 'complete the calculation upper_A = 1 + uSq / 16384 * P1 'oddly enough, upper_B calculates without any issues - JLatham upper_B = uSq / 1024 * (256 + uSq * (-128 + uSq * (74 - 47 * uSq))) 'the original calculation is "Too Complex" for Excel VBA to deal with 'so it is broken into segments to calculate without that issue 'the original implementation to calculate deltaSigma 'deltaSigma = upper_B * sinSigma * (cos2SigmaM + upper_B / 4 * _ (cosSigma * (-1 + 2 * cos2SigmaM ^ 2) _ - upper_B / 6 * cos2SigmaM * (-3 + 4 * sinSigma ^ 2) * _ (-3 + 4 * cos2SigmaM ^ 2))) 'calculate pieces of the deltaSigma formula 'broken into 3 pieces to prevent overflow error that may occur in 'Excel 2010 64-bit version. P1 = (-3 + 4 * sinSigma ^ 2) * (-3 + 4 * cos2SigmaM ^ 2) P2 = upper_B * sinSigma P3 = (cos2SigmaM + upper_B / 4 * (cosSigma * (-1 + 2 * cos2SigmaM ^ 2) _ - upper_B / 6 * cos2SigmaM * P1)) 'complete the deltaSigma calculation deltaSigma = P2 * P3 'calculate the distance s = low_b * upper_A * (sigma - deltaSigma) 'round distance to millimeters distVincenty = Round(s, 3) End Function Function SignIt(Degree_Dec As String) As Double 'Input: a string representation of a lat or long in the ' format of 10° 27' 36" S/N or 10~ 27' 36" E/W 'OUTPUT: signed decimal value ready to convert to radians ' Dim decimalValue As Double Dim tempString As String tempString = UCase(Trim(Degree_Dec)) decimalValue = Convert_Decimal(tempString) If Right(tempString, 1) = "S" Or Right(tempString, 1) = "W" Then decimalValue = decimalValue * -1 End If SignIt = decimalValue End Function Function Convert_Degree(Decimal_Deg) As Variant 'source: https://support.microsoft.com/kb/213449 ' 'converts a decimal degree representation to deg min sec 'as 10.46 returns 10° 27' 36" ' Dim degrees As Variant Dim minutes As Variant Dim seconds As Variant With Application 'Set degree to Integer of Argument Passed degrees = Int(Decimal_Deg) 'Set minutes to 60 times the number to the right 'of the decimal for the variable Decimal_Deg minutes = (Decimal_Deg - degrees) * 60 'Set seconds to 60 times the number to the right of the 'decimal for the variable Minute seconds = Format(((minutes - Int(minutes)) * 60), "0") 'Returns the Result of degree conversion '(for example, 10.46 = 10° 27' 36") Convert_Degree = " " & degrees & "° " & Int(minutes) & "' " _ & seconds + Chr(34) End With End Function Function Convert_Decimal(Degree_Deg As String) As Double 'source: https://support.microsoft.com/kb/213449 ' Declare the variables to be double precision floating-point. ' Converts text angular entry to decimal equivalent, as: ' 10° 27' 36" returns 10.46 ' alternative to ° is permitted: Use ~ instead, as: ' 10~ 27' 36" also returns 10.46 Dim degrees As Double Dim minutes As Double Dim seconds As Double ' 'modification by JLatham 'allow the user to use the ~ symbol instead of ° to denote degrees 'since ~ is available from the keyboard and ° has to be entered 'through [Alt] [0] [1] [7] [6] on the number pad. Degree_Deg = Replace(Degree_Deg, "~", "°") ' Set degree to value before "°" of Argument Passed. degrees = Val(Left(Degree_Deg, InStr(1, Degree_Deg, "°") - 1)) ' Set minutes to the value between the "°" and the "'" ' of the text string for the variable Degree_Deg divided by ' 60. The Val function converts the text string to a number. minutes = Val(Mid(Degree_Deg, InStr(1, Degree_Deg, "°") + 2, _ InStr(1, Degree_Deg, "'") - InStr(1, Degree_Deg, "°") - 2)) / 60 ' Set seconds to the number to the right of "'" that is ' converted to a value and then divided by 3600. seconds = Val(Mid(Degree_Deg, InStr(1, Degree_Deg, "'") + _ 2, Len(Degree_Deg) - InStr(1, Degree_Deg, "'") - 2)) / 3600 Convert_Decimal = degrees + minutes + seconds End Function Private Function toRad(ByVal degrees As Double) As Double toRad = degrees * (PI / 180) End Function Private Function Atan2(ByVal X As Double, ByVal Y As Double) As Double ' code nicked from: ' https://en.wikibooks.org/wiki/Programming:Visual_Basic_Classic ' /Simple_Arithmetic#Trigonometrical_Functions ' If you re-use this watch out: the x and y have been reversed from typical use. If Y > 0 Then If X >= Y Then Atan2 = Atn(Y / X) ElseIf X <= -Y Then Atan2 = Atn(Y / X) + PI Else Atan2 = PI / 2 - Atn(X / Y) End If Else If X >= -Y Then Atan2 = Atn(Y / X) ElseIf X <= Y Then Atan2 = Atn(Y / X) - PI Else Atan2 = -Atn(X / Y) - PI / 2 End If End If End Function '====================================== `

Tags: excelexcel, vba