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# Find oldest/youngest datetime object in a list

Questions:

I’ve got a list of datetime objects, and I want to find the oldest or youngest one. Some of these dates might be in the future.

``````from datetime import datetime

datetime_list = [
datetime(2009, 10, 12, 10, 10),
datetime(2010, 10, 12, 10, 10),
datetime(2010, 10, 12, 10, 10),
datetime(2011, 10, 12, 10, 10), #future
datetime(2012, 10, 12, 10, 10), #future
]
``````

What’s the most optimal way to do so? I was thinking of comparing datetime.now() to each one of those.

Oldest:

``````oldest = min(datetimes)
``````

Youngest before now:

``````now = datetime.datetime.now(pytz.utc)
youngest = max(dt for dt in datetimes if dt < now)
``````

Questions:

Given a list of dates `dates`:

Max date is `max(dates)`

Min date is `min(dates)`

Questions:

Datetimes are comparable; so you can use `max(datetimes_list)` and `min(datetimes_list)`

Questions:

have u tried this :

``````>>> from datetime import datetime as DT
>>> l =[]
>>> l.append(DT(1988,12,12))
>>> l.append(DT(1979,12,12))
>>> l.append(DT(1979,12,11))
>>> l.append(DT(2011,12,11))
>>> l.append(DT(2022,12,11))
>>> min(l)
datetime.datetime(1979, 12, 11, 0, 0)
>>> max(l)
datetime.datetime(2022, 12, 11, 0, 0)
``````