What is the Pythonic approach to achieve the following?
# Original lists: list_a = [1, 2, 3, 4] list_b = [5, 6, 7, 8] # List of tuples from 'list_a' and 'list_b': list_c = [(1,5), (2,6), (3,7), (4,8)]
Each member of
list_c is a tuple, whose first member is from
list_a and the second is from
>>> list_a = [1, 2, 3, 4] >>> list_b = [5, 6, 7, 8] >>> zip(list_a, list_b) [(1, 5), (2, 6), (3, 7), (4, 8)]
In python 3.0 zip returns a zip object. You can get a list out of it by calling
Youre looking for the builtin function zip.
You can use map lambda
a = [2,3,4] b = [5,6,7] c = map(lambda x,y:(x,y),a,b)
This will also work if there lengths of original lists do not match
I know this is an old question and was already answered, but for some reason, I still wanna post this alternative solution. I know it’s easy to just find out which built-in function does the “magic” you need, but it doesn’t hurt to know you can do it by yourself.
>>> list_1 = ['Ace', 'King'] >>> list_2 = ['Spades', 'Clubs', 'Diamonds'] >>> deck =  >>> for i in range(max((len(list_1),len(list_2)))): while True: try: card = (list_1[i],list_2[i]) except IndexError: if len(list_1)>len(list_2): list_2.append('') card = (list_1[i],list_2[i]) elif len(list_1)<len(list_2): list_1.append('') card = (list_1[i], list_2[i]) continue deck.append(card) break >>> >>> #and the result should be: >>> print deck >>> [('Ace', 'Spades'), ('King', 'Clubs'), ('', 'Diamonds')]
The output which you showed in problem statement is not the tuple but list
list_c = [(1,5), (2,6), (3,7), (4,8)]
considering you want the result as tuple out of list_a and list_b, do