Am passing a value using href tag
In first page Href tag used as
echo "<a href=view_exp.php?compna=",$compname,">$compname</a>";
In the Second page used
$compname = $_GET['compna'];
To receive the Compna values are pass but only the first word is passed remaining words are skipped.
Compname as ” Chiti Technologies Ltd ”
When I pass the value I receive onlt “Chiti”
The reason you’re only getting the first word of the company name is that the company name contains blanks. You need to encode the name.
echo "<a href=view_exp.php?compna=",urlencode($compname),">$compname</a>";
Answer：
You are producing ambiguous/invalid HTML by not quoting the parameter. The result is something like:
<a href=foo bar baz>
Only foo is recognized to belong to href, the rest doesn’t. Quote the values:
echo '<a href="view_exp.php?compna=', urlencode($compname), '">', htmlspecialchars($compname), '</a>';
Answer：
Use this code:
echo '<a href="view_exp.php?compna='.urlencode($compname).'">'.$compname.'</a>';
Answer：
You need add quotes for your href, besides, you also need to use urlencode to encode the variable.
echo '<a href="view_exp.php?compna=' . urlencode($compname) . '">' . $compname . '</a>';
Answer：
change echo "<a href=view_exp.php?compna=",$compname,">$compname</a>";
to echo "<a href=\"view_exp.php?compna=$compname\">$compname</a>";
When using double quoted strings ” you don’t need to paste variables in between, you can just type them.
Also, when pasting strings together don’t use comma’s , but use . to paste strings otherwise you’ll get parse errors.
For arrays include them between curly brackets {}
echo "<a href=\"view_exp.php?compna={$compname["whatever"]}\">$compname</a>";
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