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How to print a linebreak in a python function?

Posted by: admin November 30, 2017 Leave a comment

Questions:

I have a list of strings in my code;

A = ['a1', 'a2', 'a3' ...]
B = ['b1', 'b2', 'b3' ...]

and I want to print them separated by a linebreak, like this:

>a1
b1
>a2
b2
>a3
b3

I’ve tried:

print '>' + A + '/n' + B

But /n isn’t recognized like a line break.

Answers:

You have your slash backwards, it should be "\n"

Questions:
Answers:

The newline character is actually '\n'.

Questions:
Answers:
for pair in zip(A, B):
    print ">"+'\n'.join(pair)

Questions:
Answers:
>>> A = ['a1', 'a2', 'a3']
>>> B = ['b1', 'b2', 'b3']

>>> for x in A:
        for i in B:
            print ">" + x + "\n" + i

Outputs:

>a1
b1
>a1
b2
>a1
b3
>a2
b1
>a2
b2
>a2
b3
>a3
b1
>a3
b2
>a3
b3

Notice that you are using /n which is not correct!

Questions:
Answers:

\n is an escape sequence, denoted by the backslash. A normal forward slash, such as /n will not do the job. In your code you are using /n instead of \n.

Questions:
Answers:

All three way you can use for newline character :

'\n'

"\n"

"""\n"""