I have a list of strings in my code;

```
A = ['a1', 'a2', 'a3' ...]
B = ['b1', 'b2', 'b3' ...]
```

and I want to print them separated by a linebreak, like this:

```
>a1
b1
>a2
b2
>a3
b3
```

I’ve tried:

```
print '>' + A + '/n' + B
```

But /n isn’t recognized like a line break.

You have your slash backwards, it should be `"\n"`

The newline character is actually `'\n'`

.

```
for pair in zip(A, B):
print ">"+'\n'.join(pair)
```

```
>>> A = ['a1', 'a2', 'a3']
>>> B = ['b1', 'b2', 'b3']
>>> for x in A:
for i in B:
print ">" + x + "\n" + i
```

Outputs:

```
>a1
b1
>a1
b2
>a1
b3
>a2
b1
>a2
b2
>a2
b3
>a3
b1
>a3
b2
>a3
b3
```

Notice that you are using `/n`

which is **not** correct!

`\n`

is an escape sequence, denoted by the backslash. A normal forward slash, such as `/n`

will not do the job. In your code you are using `/n`

instead of `\n`

.

All three way you can use for newline character :

```
'\n'
"\n"
"""\n"""
```