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How to read a large text file line by line using Java?

Posted by: admin November 2, 2017 Leave a comment

Questions:

I need to read a large text file of around 5-6 GB line by line using Java.

How can I do this quickly?

Answers:

A common pattern is to use

try (BufferedReader br = new BufferedReader(new FileReader(file))) {
    String line;
    while ((line = br.readLine()) != null) {
       // process the line.
    }
}

You can read the data faster if you assume there is no character encoding. e.g. ASCII-7 but it won’t make much difference. It is highly likely that what you do with the data will take much longer.

EDIT: A less common pattern to use which avoids the scope of line leaking.

try(BufferedReader br = new BufferedReader(new FileReader(file))) {
    for(String line; (line = br.readLine()) != null; ) {
        // process the line.
    }
    // line is not visible here.
}

UPDATE: In Java 8 you can do

try (Stream<String> stream = Files.lines(Paths.get(fileName))) {
        stream.forEach(System.out::println);
}

NOTE: You have to place the Stream in a try-with-resource block to ensure the file is closed. If you don’t do this, the GC might clean up/close the file before you run out of file handles (or it might not)

Questions:
Answers:

Look at this blog:

The buffer size may be specified, or
the default size may be used. The
default is large enough for most
purposes.

// Open the file
FileInputStream fstream = new FileInputStream("textfile.txt");
BufferedReader br = new BufferedReader(new InputStreamReader(fstream));

String strLine;

//Read File Line By Line
while ((strLine = br.readLine()) != null)   {
  // Print the content on the console
  System.out.println (strLine);
}

//Close the input stream
br.close();

Questions:
Answers:

Once is out (March 2014) you’ll be able to use streams:

try (Stream<String> lines = Files.lines(Paths.get(filename), Charset.defaultCharset())) {
  lines.forEachOrdered(line -> process(line));
}

Printing all the lines in the file:

try (Stream<String> lines = Files.lines(file, Charset.defaultCharset())) {
  lines.forEachOrdered(System.out::println);
}

Questions:
Answers:

Here is a sample with full error handling and supporting charset specification for pre-Java 7. With Java 7 you can use try-with-resources syntax, which makes the code cleaner.

If you just want the default charset you can skip the InputStream and use FileReader.

InputStream ins = null; // raw byte-stream
Reader r = null; // cooked reader
BufferedReader br = null; // buffered for readLine()
try {
    String s;
    if (true) {
        String data = "#foobar\t1234\n#xyz\t5678\none\ttwo\n";
        ins = new ByteArrayInputStream(data.getBytes());
    } else {
        ins = new FileInputStream("textfile.txt");
    }
    r = new InputStreamReader(ins, "UTF-8"); // leave charset out for default
    br = new BufferedReader(r);
    while ((s = br.readLine()) != null) {
        System.out.println(s);
    }
}
catch (Exception e)
{
    System.err.println(e.getMessage()); // handle exception
}
finally {
    if (br != null) { try { br.close(); } catch(Throwable t) { /* ensure close happens */ } }
    if (r != null) { try { r.close(); } catch(Throwable t) { /* ensure close happens */ } }
    if (ins != null) { try { ins.close(); } catch(Throwable t) { /* ensure close happens */ } }
}

Here is the Groovy version, with full error handling:

File f = new File("textfile.txt");
f.withReader("UTF-8") { br ->
    br.eachLine { line ->
        println line;
    }
}

Questions:
Answers:

In Java 8, you could do:

try (Stream<String> lines = Files.lines (file, StandardCharsets.UTF_8))
{
    for (String line : (Iterable<String>) lines::iterator)
    {
        ;
    }
}

Some notes: The stream returned by Files.lines (unlike most streams) needs to be closed. For the reasons mentioned here I avoid using forEach(). The strange code (Iterable<String>) lines::iterator casts a Stream to an Iterable.

Questions:
Answers:

What you can do is scan the entire text using Scanner and go through the text line by line.
Of course you should import the following:

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public static void readText throws FileNotFoundException {
    Scanner scan = new Scanner(new File("samplefilename.txt"));
    while(scan.hasNextLine()){
        String line = scan.nextLine();
        //Here you can manipulate the string the way you want
    }
}

Scanner basically scans all the text. The while loop is used to traverse through the entire text.

The .hasNextLine() function is a boolean that returns true if there are still more lines in the text. The .nextLine() function gives you an entire line as a String which you can then use the way you want. Try System.out.println(line) to print the text.

Side Note: .txt is the file type text.

Questions:
Answers:

FileReader won’t let you specify the encoding, use InputStreamReaderinstead if you need to specify it:

try {
    BufferedReader br = new BufferedReader(new InputStreamReader(new FileInputStream(filePath), "Cp1252"));         

    String line;
    while ((line = br.readLine()) != null) {
        // process the line.
    }
    br.close();

} catch (IOException e) {
    e.printStackTrace();
}

If you imported this file from Windows, it might have ANSI encoding (Cp1252), so you have to specify the encoding.

Questions:
Answers:

In Java 7:

String folderPath = "C:/folderOfMyFile";
Path path = Paths.get(folderPath, "myFileName.csv"); //or any text file eg.: txt, bat, etc
Charset charset = Charset.forName("UTF-8");

try (BufferedReader reader = Files.newBufferedReader(path , charset)) {
  while ((line = reader.readLine()) != null ) {
    //separate all csv fields into string array
    String[] lineVariables = line.split(","); 
  }
} catch (IOException e) {
    System.err.println(e);
}

Questions:
Answers:

You can use Scanner class

Scanner sc=new Scanner(file);
sc.nextLine();

Questions:
Answers:

You need to use the readLine() method in class BufferedReader.
Create a new object from that class and operate this method on him and save it to a string.

BufferReader Javadoc

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Answers:

In Java 8, there is also an alternative to using Files.lines(). If your input source isn’t a file but something more abstract like a Reader or an InputStream, you can stream the lines via the BufferedReaders lines() method.

For example:

try( BufferedReader reader = new BufferedReader( ... ) ) {
  reader.lines().foreach( line -> processLine( line ) );
}

will call processLine() for each input line read by the BufferedReader.

Questions:
Answers:

Java-9 :

try (Stream<String> stream = Files.lines(Paths.get(fileName))) {
        stream.forEach(System.out::println);
}

Questions:
Answers:

For Reading file with java 8

  package com.java.java8;

    import java.nio.file.Files;
    import java.nio.file.Paths;
    import java.util.stream.Stream;

    /**
     * The Class ReadLargeFile.
     *
     * @author Ankit Sood Apr 20, 2017
     */
    public class ReadLargeFile {

        /**
         * The main method.
         *
         * @param args
         *            the arguments
         */
        public static void main(String[] args) {
        try {
            Stream<String> stream = Files.lines(Paths.get("C:\Users\System\Desktop\demoData.txt"));
            stream.forEach(System.out::println);
        } catch (Exception e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }
        }
    }

Questions:
Answers:

The clear way to achieve this,

For example:

If you have dataFile.txt on your current directory

import java.io.*;
import java.util.Scanner;
import java.io.FileNotFoundException;

public class readByLine
{
    public readByLine() throws FileNotFoundException
    {
        Scanner linReader = new Scanner(new File("dataFile.txt"));

        while (linReader.hasNext())
        {
            String line = linReader.nextLine();
            System.out.println(line);
        }
        linReader.close();

    }

    public static void main(String args[])  throws FileNotFoundException
    {
        new readByLine();
    }
}

The output like as below,
enter image description here

Questions:
Answers:

I usually do the reading routine straightforward:

void readResource(InputStream source) throws IOException {
    BufferedReader stream = null;
    try {
        stream = new BufferedReader(new InputStreamReader(source));
        while (true) {
            String line = stream.readLine();
            if(line == null) {
                break;
            }
            //process line
            System.out.println(line)
        }
    } finally {
        closeQuiet(stream);
    }
}

static void closeQuiet(Closeable closeable) {
    if (closeable != null) {
        try {
            closeable.close();
        } catch (IOException ignore) {
        }
    }
}

Questions:
Answers:
BufferedReader br;
FileInputStream fin;
try {
    fin = new FileInputStream(fileName);
    br = new BufferedReader(new InputStreamReader(fin));

    /*Path pathToFile = Paths.get(fileName);
    br = Files.newBufferedReader(pathToFile,StandardCharsets.US_ASCII);*/

    String line = br.readLine();
    while (line != null) {
        String[] attributes = line.split(",");
        Movie movie = createMovie(attributes);
        movies.add(movie);
        line = br.readLine();
    }
    fin.close();
    br.close();
} catch (FileNotFoundException e) {
    System.out.println("Your Message");
} catch (IOException e) {
    System.out.println("Your Message");
}

It works for me. Hope It will help you too.

Questions:
Answers:

You can also use apache commons io:

File file = new File("/home/user/file.txt");
try {
    List<String> lines = FileUtils.readLines(file);
} catch (IOException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}

Questions:
Answers:

You can use this code:

import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;

public class ReadTextFile {

    public static void main(String[] args) throws IOException {

        try {

            File f = new File("src/com/data.txt");

            BufferedReader b = new BufferedReader(new FileReader(f));

            String readLine = "";

            System.out.println("Reading file using Buffered Reader");

            while ((readLine = b.readLine()) != null) {
                System.out.println(readLine);
            }

        } catch (IOException e) {
            e.printStackTrace();
        }

    }

}

Questions:
Answers:

You can use streams to do it more precisely:

Files.lines(Paths.get("input.txt")).forEach(s -> stringBuffer.append(s);