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Is there a JavaScript strcmp()?

Posted by: admin November 30, 2017 Leave a comment

Questions:

Can anyone verify this for me? JavaScript does not have a version of strcmp(), so you have to write out something like:

 ( str1 < str2 ) ? 
            -1 : 
             ( str1 > str2 ? 1 : 0 );
Answers:

What about

str1.localeCompare(str2)

Questions:
Answers:

Javascript doesn’t have it, as you point out.

A quick search came up with:

function strcmp ( str1, str2 ) {
    // http://kevin.vanzonneveld.net
    // +   original by: Waldo Malqui Silva
    // +      input by: Steve Hilder
    // +   improved by: Kevin van Zonneveld (http://kevin.vanzonneveld.net)
    // +    revised by: gorthaur
    // *     example 1: strcmp( 'waldo', 'owald' );
    // *     returns 1: 1
    // *     example 2: strcmp( 'owald', 'waldo' );
    // *     returns 2: -1

    return ( ( str1 == str2 ) ? 0 : ( ( str1 > str2 ) ? 1 : -1 ) );
}

from http://kevin.vanzonneveld.net/techblog/article/javascript_equivalent_for_phps_strcmp/

Of course, you could just add localeCompare if needed:

if (typeof(String.prototype.localeCompare) === 'undefined') {
    String.prototype.localeCompare = function(str, locale, options) {
        return ((this == str) ? 0 : ((this > str) ? 1 : -1));
    };
}

And use str1.localeCompare(str2) everywhere, without having to worry wether the local browser has shipped with it. The only problem is that you would have to add support for locales and options if you care about that.

Questions:
Answers:

localeCompare() is slow, so if you don’t care about the “correct” ordering of non-English-character strings, try your original method or the cleaner-looking:

str1 < str2 ? -1 : +(str1 > str2)

This is an order of magnitude faster than localeCompare() on my machine.

The + ensures that the answer is always numeric rather than boolean.

Questions:
Answers:

How about:

String.prototype.strcmp = function(s) {
    if (this < s) return -1;
    if (this > s) return 1;
    return 0;
}

Then, to compare s1 with 2:

s1.strcmp(s2)

Questions:
Answers:

Try this more compact and easy to understand statement

(a>b)-(a<b)

It is approx. 50% slower than

(a<b)?-1:((a>b)?1:0)