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java – Access resource files in Android

Posted by: admin April 23, 2020 Leave a comment

Questions:

I have a resource file in my /res/raw/ folder (/res/raw/textfile.txt) which I am trying to read from my android app for processing.

public static void main(String[] args) {

    File file = new File("res/raw/textfile.txt");

    FileInputStream fis = null;
    BufferedInputStream bis = null;
    DataInputStream dis = null;

    try {
      fis = new FileInputStream(file);
      bis = new BufferedInputStream(fis);
      dis = new DataInputStream(bis);

      while (dis.available() != 0) {
              // Do something with file
          Log.d("GAME", dis.readLine()); 
      }

      fis.close();
      bis.close();
      dis.close();

    } catch (FileNotFoundException e) {
      e.printStackTrace();
    } catch (IOException e) {
      e.printStackTrace();
    }
  }

I have tried different path syntax but always get a java.io.FileNotFoundException error. How can I access /res/raw/textfile.txt for processing? Is File file = new File(“res/raw/textfile.txt”); the wrong method in Android?


* Answer: *

// Call the LoadText method and pass it the resourceId
LoadText(R.raw.textfile);

public void LoadText(int resourceId) {
    // The InputStream opens the resourceId and sends it to the buffer
    InputStream is = this.getResources().openRawResource(resourceId);
    BufferedReader br = new BufferedReader(new InputStreamReader(is));
    String readLine = null;

    try {
        // While the BufferedReader readLine is not null 
        while ((readLine = br.readLine()) != null) {
        Log.d("TEXT", readLine);
    }

    // Close the InputStream and BufferedReader
    is.close();
    br.close();

    } catch (IOException e) {
        e.printStackTrace();
    }
}
How to&Answers:

If you have a file in res/raw/textfile.txt from your Activity/Widget call:

getResources().openRawResource(...) returns an InputStream

The dots should actually be an integer found in R.raw… corresponding to your filename, possibly R.raw.textfile (it’s usually the name of the file without extension)

new BufferedInputStream(getResources().openRawResource(...)); then read the content of the file as a stream