I am writing a get API for getting excel sheet file stored in src/main/resources.
The InputStream has the content of excel file (xlsm format). But the response is having corrupted data.
@GetMapping("/downloadTemplate")
public ResponseEntity<?> downloadTemplate() throws IOException {
String fn = "filename";
try {
File file = new File(getClass().getClassLoader().getResource(fn).getFile());
InputStreamSource iss = new FileSystemResource(file);
return ResponseEntity.ok()
.header(HttpHeaders.CONTENT_TYPE, MediaType.APPLICATION_OCTET_STREAM_VALUE)
.header(HttpHeaders.CONTENT_DISPOSITION, "attachment; filename= SimpleStandardTemplate.xlsm")
.body(IOUtils.toByteArray(iss.getInputStream()));
} catch (Exception e) {
log.error("An error occurred while trying to downloadTemplate: {}", e);
throw new ApiException(ApiErrorCode.DEFAULT_410, "Error while downloading");
}
}
Seems like this line has a problem “body(IOUtils.toByteArray(iss.getInputStream()));” . If yet any alternate way? Else what could be the issue?
Edit: I think the issue is with content length.
Try this, tested with spring-boot 1.5.6
@GetMapping("/export")
public ResponseEntity<Resource> download() throws IOException {
String fileName ="<file-path>";
Resource resource = new FileSystemResource(fileName);
return ResponseEntity.ok()
.contentType(MediaType.parseMediaType(MediaType.APPLICATION_OCTET_STREAM_VALUE))
.header(HttpHeaders.CONTENT_DISPOSITION, "attachment; filename=\"" + resource.getFilename() + "\"")
.body(resource);
}
Answer:
One potential problem is that your original file is not xlsm file. For example, Excel doesn’t allow you to open a normal xlsx file under macro enabled mode. Please double check.
Answer:
I think your MIME type is wrong, Refer this for excel Mime types, I have change the way you send the file using Spring's
FileSystemResource
@GetMapping(value = "/downloadTemplate", produces = "application/vnd.ms-excel.sheet.macroEnabled.12")
public FileSystemResource downloadTemplate(HttpServletResponse response) throws IOException {
String fn = "filename";
File file = new File(getClass().getClassLoader().getResource(fn).getFile());
response.setHeader(HttpHeaders.CONTENT_DISPOSITION, "attachment; filename= SimpleStandardTemplate.xlsm");
return new FileSystemResource(file); // You could directly pass the absolute path of the file
}