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java – How to convert String to its resource ID (Android Studio)

Posted by: admin June 15, 2020 Leave a comment


I have an xml string in my values/strings.xml file

    <string name="pokemon_d">150</string>

And I have the String "150" in my controller MainActivity.java. In my MainActivity, how can I convert that String to the resource ID of the pokemon_d String in the xml file? Is this even possible?

How to&Answers:

You can not get identifier by value, but you can make your identifier name look like a value and get it by string name,

So what I suggest,

use your String resource name something like, resource_150

<string name="resource_150">150</string>

Now here resource_ is common for your string entries in string.xml file, so
in your code,

String value = "150";
int resourceId = this.getResources().
             getIdentifier("resource_"+value, "string", this.getPackageName());

Now resourceId value is as equivalent to R.string.resource_150

Just make sure here this represent your application context. In your case MainActivity.this will work.


I have found some tips here: Android, getting resource ID from string?

Below an example how to get strings and their values defined in strings.xml. The only thing you have to do is making a loop and test which string is holding your value. If you need to repeat this many times it might be better to build an array.

    String strField = "";
    int resourceId = -1;
    String sClassName = getPackageName() + ".R$string";
    try {
        Class classToInvestigate = Class.forName(sClassName); 

        Field fields[] = classToInvestigate.getDeclaredFields();

        strField = fields[0].getName();     
        resourceId = getResourceId(strField,"string",getPackageName());

        String test = getResources().getString(resourceId);

                       "Field: " + strField + " value: " + test ,

    } catch (ClassNotFoundException e) {
                       "Class not found" ,
    } catch (Exception e) {
                       "Error: " + e.getMessage() ,

public int getResourceId(String pVariableName, String pResourcename, String pPackageName) 
    try {
        return getResources().getIdentifier(pVariableName, pResourcename, pPackageName);
    } catch (Exception e) {
        return -1;



You can’t search for a resource Id by the string value. You could make your own Map of the values and resourceIds and use that as a look up table, but I believe just choosing an intelligent naming convention like in the accepted answer is the best solution.