I have a xml URL file in which there are white spaces i want to replace white spaces with %20.. how to do this????
SAXParserFactory spf = SAXParserFactory.newInstance();
SAXParser sp = spf.newSAXParser();
XMLReader xr = sp.getXMLReader();
/** Send URL to parse XML Tags */
URL sourceUrl = new URL(
"http://www.arteonline.mobi/iphone/output.php?gallery=MALBA%20-%20MUSEO%20DE%20ARTE%20LATINOAMERICANO%20DE%20BUENOS%20AIRES");
XMLHandlerartistspace myXMLHandler = new XMLHandlerartistspace();
xr.setContentHandler(myXMLHandler);
xr.parse(new InputSource(sourceUrl.openStream()));
Try this:
String temp = http://www.arteonline.mobi/iphone/output.php?gallery=MALBA%20-%20MUSEO%20DE%20ARTE%20LATINOAMERICANO%20DE%20BUENOS%20AIRES
temp = temp.replaceAll(" ", "%20");
URL sourceUrl = new URL(temp);
Answer：
When you build your URL you should use URLEncoder to encode the parameters.
StringBuilder query = new StringBuilder();
query.append("gallery=");
query.append(URLEncoder.encode(value, "UTF-8"));
If you already have the whole URL in a String or a java.net.URL, you could grab the query part and rebuild while URLEncoding each parameter value.
Answer：
Just one addition to sudocode’s response:
Use android.net.Uri.encode instead of URLEncoder.encode to avoid the “spaces getting converted into +” problem. Then you get rid of the String.replaceAll() and it’s more elegant 🙂
StringBuilder query = new StringBuilder();
query.append("gallery=");
query.append(android.net.Uri.encode(value));
Answer：
I guess you want to replace all spaces, not only white.
the simplest way is to use
"url_with_spaces".replaceAll(" ", "%20);
However you should consider also other characters in the url. See Recommended method for escaping HTML in Java
Answer：
String s = "my string";
s=s.replaceAll(" ", "%20");
Answer：
Try using URIUtil.encodePath method from the api org.apache.commons.httpclient.util.URIUtil.
This should do the trick for you.
Answer：
For anyone that needs space characters to be encoded as a %20 value instead of a + value, use:
String encodedString = URLEncoder.encode(originalString,"UTF-8").replaceAll("\+", "%20")
