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Java lambda sublist

Posted by: admin December 28, 2021 Leave a comment

Questions:

What is the shortest way to express “get new List B from List A where condition” via a Java 8 lambda?

Say I have List<Integer> a = Arrays.asList(1, 2, 3, 4, 5) and I want a new List, B, where the value is > 3.

I’ve read through the new Collections Streams API, but I’m not convinced I have found the best way to do this, and don’t want to taint the question with what is probably my less than perfect solution.

Answers:
a.stream().filter(x -> x > 3).collect(Collectors.toList());