Home » Jquery » jQuery Autosize plugin error – intermediate value(…) is not a function

jQuery Autosize plugin error – intermediate value(…) is not a function

Posted by: admin November 29, 2017 Leave a comment

Questions:

I use jQuery Autosize plugin:

http://www.jacklmoore.com/autosize/

The script itself you can see here:

http://www.jacklmoore.com/js/jquery.autosize.js

This is how I use the script:

jQuery(function($){$(document).ready(function(){
$('textarea').autosize();
}

Problem N 1

Just updated the script to the latest version and it stopped to work:

"TypeError: (intermediate value)(...) is not a function"

Javascript console reports this error on the last line of the script:

}(window.jQuery || window.$)); 

Problem N 2

Script doesn’t work in modal windows (PrettyPhoto) and javascript console doesn’t show any errors.

Any ideas?

Answers:

the "TypeError: (intermediate value)(...) is not a function"
pops up as the result of missing a semi colon on the function BEFORE the one it throws an error on. It might be as simple as:

jQuery(function($){$(document).ready(function(){
$('textarea').autosize();
}  
); //<-----

or it could be the function declared before that.
An example of how this is cause is in this code:

var populate = function(sw) {
  myglobalswitch = sw;
  window.setTimeout(repopulate, 250, sw);
}

(function( $ ) {
$.widget( "custom.combobox", {
_create: function() {
....
})( jQuery );

results in the Intermediate value is not… on the last line: })( jQuery );

However, the fix is adding a semi colon to the populate function:

var populate = function(sw) {
  myglobalswitch = sw;
  window.setTimeout(repopulate, 250, sw);
}  ;

to prevent the parser from thinking that “var populate = … ” and (function($) … are a single statement, the second extending from the first.

Questions:
Answers:

FWIW the autosize invocation method has changed. If you end up here and are using it with jQuery

Previously it was

$('textarea').autosize();

The new invocation is

autosize($('textarea'));

Questions:
Answers:

You may have declared a function, inside a function, after you needed it. This was my problem.