I’m using Doctrine’s querybuilder in Symfony2 to create a query to fetch entities.
My current code looks like this:
$repository = $this->getDoctrine()->getRepository('AaaBundle:Application'); $queryBuilder = $repository->createQueryBuilder('a'); $queryBuilder ->addSelect('u') ->addSelect('i') ->orderBy('a.created_date', 'DESC') ->leftJoin('a.created_by', 'u') ->leftJoin('a.installations', 'i') //->where('i.page = :page') //->setParameter('page', $found) ;
Now I can use this to get all the pages regardless of them having an installation or not.
But I only want to join them it the
$found page is available (so that if there is an installation for the app, but it’s on another page, the installation wont be joined). If I unquote the where clause, it will show only apps that have an installation for the page. I want all apps with or without installations for the page.
In SQL I can get this by adding
AND to the join
LEFT JOIN installations i ON a.id = i.app AND i.page = :page
This way I get the installation info for an app that has an installation on the page, but I get null values on the columns for app’s that have installations on other pages or not at all.
Is there a way to do this in Doctrine or am I better off just getting all the installations for each application and then checking against the found page with php?
You can try this :
use Doctrine\ORM\Query\Expr; ->leftJoin('a.installations', 'i', Expr\Join::WITH, 'i.page = :page') ->setParameter('page', $page)
See function leftJoin in doc: http://docs.doctrine-project.org/projects/doctrine-orm/en/latest/reference/query-builder.html#high-level-api-methods