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php – Check if specific input file is empty

Posted by: admin April 23, 2020 Leave a comment

Questions:

In my form I have 3 input fields for file upload:

<input type=file name="cover_image">
<input type=file name="image1">
<input type=file name="image2">

How can I check if cover_image is empty – no file is put for upload?

How to&Answers:

You can check by using the size field on the $_FILES array like so:

if ($_FILES['cover_image']['size'] == 0 && $_FILES['cover_image']['error'] == 0)
{
    // cover_image is empty (and not an error)
}

(I also check error here because it may be 0 if something went wrong. I wouldn’t use name for this check since that can be overridden)

Answer:

Method 1

if($_FILES['cover_image']['name'] == "") {
// No file was selected for upload, your (re)action goes here
}

Method 2

if($_FILES['cover_image']['size'] == 0) {
// No file was selected for upload, your (re)action goes here
}

Answer:

You can check if there is a value, and if the image is valid by doing the following:

if(empty($_FILES['cover_image']['tmp_name']) || !is_uploaded_file($_FILES['cover_image']['tmp_name']))
{
   // Handle no image here...
}

Answer:

if (empty($_FILES['cover_image']['name']))

Answer:

simple :

if($_FILES['cover_image']['error'] > 0)
    // cover_image is empty

Answer:

check after the form is posted the following

$_FILES["cover_image"]["size"]==0

Answer:

 if( ($_POST) && (!empty($_POST['cover_image'])) )    //verifies  if post exists and cover_image is not empty
    {
    //execute whatever code you want
    }

Answer:

if($_FILES['img_name']['name']!=""){
   echo "File Present";
}else{
  echo "Empty file";
}

Answer:

if ($_FILES['cover_image']['size'] == 0 && $_FILES['cover_image']['error'] == 0)
{ 
      // Code comes here
}

This thing works for me……..