I’m attempting to display an image stored in the BLOB column in the database;
I fetch the data from the database with a SELECT perform no transformations on the data and display it with the following (from a script whose only output is the following):
header("Content-Type: image/jpeg");
echo $image;
Please note chrome is displaying the content size as the correct size for the image as well as the correct mime type (image/jpeg
). nothing is echoing out before the header and ive checked the blob in the database is correct. There is also no trailing whitespace before or after the <?php ?>
tags.
chrome/IE displays an image icon but not the image itself. any ideas?
EDIT: image is got the from the database as such:
$sql = "SELECT * FROM products WHERE id = $id";
$sth = $db->query($sql);
$row = $sth->fetch();
$image = $row['image'];
var_dump($image) gives:
string 'ÿØÿà�JFIF��x�x��ÿá�ZExif��MM�*�����������J��������Q�������Q������tQ������t�����† ��±ÿÛ�C�
ÿÛ�CÿÀ�_"�ÿÄ�����������
ÿÄ�µ���}�!1AQa"q2‘¡#B±ÁRÑð$3br‚
%&'()*456789:CDEFGHIJSTUVWXYZcdefghijstuvwxyzƒ„…†‡ˆ‰Š’“”•–—˜™š¢£¤¥¦§¨©ª²³ ´µ¶·¸¹ºÂÃÄÅÆÇÈÉÊÒÓÔÕÖרÙÚáâãäåæçèéêñòóôõö÷øùúÿÄ��������'... (length=60766)
Try Like this.
For Inserting into DB
$db = mysqli_connect("localhost","root","","DbName"); //keep your db name
$image = addslashes(file_get_contents($_FILES['images']['tmp_name']));
//you keep your column name setting for insertion. I keep image type Blob.
$query = "INSERT INTO products (id,image) VALUES('','$image')";
$qry = mysqli_query($db, $query);
For Accessing image From Blob
$db = mysqli_connect("localhost","root","","DbName"); //keep your db name
$sql = "SELECT * FROM products WHERE id = $id";
$sth = $db->query($sql);
$result=mysqli_fetch_array($sth);
echo '<img src="data:image/jpeg;base64,'.base64_encode( $result['image'] ).'"/>';
Hope It will help you.
Thanks.
Answer:
This is what I use to display images from blob:
echo '<img src="data:image/jpeg;base64,'.base64_encode($image->load()) .'" />';
Answer:
Since I have to store various types of content in my blob field/column, I am suppose to update my code like this:
echo "data: $mime" $result['$data']";
where:
mime
can be an image of any kind, text, word document, text document, PDF document, etc… content datatype is blob
in database.