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php – Fatal error: Using $this when not in object context

Posted by: admin July 12, 2020 Leave a comment

Questions:

here is the part if having error.

Fatal error: Using $this when not in
object context in
/pb_events.php
on line 6

line 6 is: $jpp = $this->vars->data["jpp"];

function DoEvents($this) {

    global $_CONF, $_PAGE, $_TSM , $base;

    $jpp = $this->vars->data["jpp"];

    $cache["departments"] = $this->db->QFetchRowArray("SELECT * FROM {$this->tables[job_departments]}");
    $cache["locations"] = $this->db->QFetchRowArray("SELECT * FROM {$this->tables[job_location]}");
    $cache["names"] = $this->db->QFetchRowArray("SELECT * FROM {$this->tables[job_names]}");
    $cache["categories"] = $this->db->QFetchRowArray("SELECT * FROM {$this->tables[job_categories]}");

Thanks a lot! appreciate!

How to&Answers:

$this only makes sense in methods, not in functions

this is ok

class Foo {
     function bar() {
          $this->...

this is not

function some() {
    $this->

// edit: didn’t notice he passes “$this” as parameter

advice: simply replace “$this” with “$somethingElse”

Answer:

You cannot pass $this to a procedural function. $this is a reserved variable.

Answer:

As per my comments.
You want to use $this as passed variable and php doesn’t allow it outside class methods body.

function DoEvents($obj) {

    global $_CONF, $_PAGE, $_TSM , $base;

    $jpp = $obj->vars->data["jpp"];

    $cache["departments"] = $obj->db->QFetchRowArray("SELECT * FROM {$obj->tables[job_departments]}");
    $cache["locations"] = $obj->db->QFetchRowArray("SELECT * FROM {$obj->tables[job_location]}");
    $cache["names"] = $obj->db->QFetchRowArray("SELECT * FROM {$obj->tables[job_names]}");
    $cache["categories"] = $obj->db->QFetchRowArray("SELECT * FROM {$obj->tables[job_categories]}");

Answer:

You have to make the object first.

   $object=new Myobject;
   DoEvents($object);