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php – How can I find the maximum and minimum date in an array?

Posted by: admin July 12, 2020 Leave a comment

Questions:

I need to find the maximum and minimum date from a given array using PHP.

I have $date_arr which contains following values,

  $date_arr = array('0'=>'20-05-2015','1'=>'02-01-2015','2'=>'30-03-2015');

Here, I need to get the larger date as ’20-05-2015′ and the minimum date as ’02-01-2015′.

How can I achieve this?

How to&Answers:
<?php

$date_arr=array(0=>'20-05-2015',1=>'02-01-2015',2=>'30-03-2015');

usort($date_arr, function($a, $b) {
    $dateTimestamp1 = strtotime($a);
    $dateTimestamp2 = strtotime($b);

    return $dateTimestamp1 < $dateTimestamp2 ? -1: 1;
});

echo 'Min: ' . $date_arr[0];
echo '<br/>';
echo 'Max: ' . $date_arr[count($date_arr) - 1];


?>

Answer:

max() and min() works fine with your array:

echo "Latest Date: ". max($dates)."\n";
echo "Earliest Date: ". min($dates)."\n";

Answer:

please Try this

$date_arr = array('0' => '20-05-2015', '1' => '02-01-2015', '2' => '30-03-2015');
for ($i = 0; $i < count($date_arr); $i++)
{
    if ($i == 0)
    {
        $max_date = date('Y-m-d H:i:s', strtotime($date_arr[$i]));
        $min_date = date('Y-m-d H:i:s', strtotime($date_arr[$i]));
    }
    else if ($i != 0)
    {
        $new_date = date('Y-m-d H:i:s', strtotime($date_arr[$i]));
        if ($new_date > $max_date)
        {
            $max_date = $new_date;
        }
        else if ($new_date < $min_date)
        {
            $min_date = $new_date;
        }
    }
}
echo date('d-m-Y',strtotime($max_date));
echo date('d-m-Y',strtotime($min_date));

Answer:

$date_arr=array(0=>'2015-05-20',1=>'2015-02-21',2=>'2015-04-13',3=>'2020-04-30',4=>'2020-04-13');

$max_date=$date_arr[0];
for($i=0;$i<count($date_arr);$i++)
{
    echo $date_arr[$i]. ' ,';
    if( $max_date < $date_arr[$i+1])
    {
        $max_date=$date_arr[$i+1];
    }
}  
echo " Max= ". $max_date;