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php – How do I get next month date from today's date and insert it in my database?

Posted by: admin April 23, 2020 Leave a comment

Questions:

I have two columns in my db: start_date and end_date, which are both DATE types. My code is updating the dates as follows:

$today_date = date("Y-m-d");
$end_date = date("Y-m-d"); // date +1 month ??

$sql1 = "UPDATE `users` SET `start_date` = '".$today_date."', `end_date` = '".$end_date."'  WHERE `users`.`id` ='".$id."' LIMIT 1 ;";

What is the best way to make $end_date equal to $start_date + one month? For example, 2000-10-01 would become 2000-11-01.

How to&Answers:

You can use PHP’s strtotime() function:

// One month from today
$date = date('Y-m-d', strtotime('+1 month'));

// One month from a specific date
$date = date('Y-m-d', strtotime('+1 month', strtotime('2015-01-01')));

Just note that +1 month is not always calculated intuitively. It appears to always add the number of days that exist in the current month.

Current Date  | +1 month
-----------------------------------------------------
2015-01-01    | 2015-02-01   (+31 days)
2015-01-15    | 2015-02-15   (+31 days)
2015-01-30    | 2015-03-02   (+31 days, skips Feb)
2015-01-31    | 2015-03-03   (+31 days, skips Feb)
2015-02-15    | 2015-03-15   (+28 days)
2015-03-31    | 2015-05-01   (+31 days, skips April)
2015-12-31    | 2016-01-31   (+31 days)

Some other date/time intervals that you can use:

$date = date('Y-m-d'); // Initial date string to use in calculation

$date = date('Y-m-d', strtotime('+1 day', strtotime($date)));
$date = date('Y-m-d', strtotime('+1 week', strtotime($date)));
$date = date('Y-m-d', strtotime('+2 week', strtotime($date)));
$date = date('Y-m-d', strtotime('+1 month', strtotime($date)));
$date = date('Y-m-d', strtotime('+30 days', strtotime($date)));

Answer:

The accepted answer works only if you want exactly 31 days later. That means if you are using the date “2013-05-31” that you expect to not be in June which is not what I wanted.

If you want to have the next month, I suggest you to use the current year and month but keep using the 1st.

$date = date("Y-m-01");
$newdate = strtotime ( '+1 month' , strtotime ( $date ) ) ;

This way, you will be able to get the month and year of the next month without having a month skipped.

Answer:

You do not actually need PHP functions to achieve this. You can already do simple date manipulations directly in SQL, for example:

$sql1 = "
    UPDATE `users` SET 
    `start_date` = CURDATE(), 
    `end_date` = DATE_ADD(CURDATE(), INTERVAL 1 MONTH)  
    WHERE `users`.`id` = '" . $id . "';
";

Refer to http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_addtime

Answer:

If you want a specific date in next month, you can do this:

// Calculate the timestamp
$expire = strtotime('first day of +1 month');

// Format the timestamp as a string
echo date('m/d/Y', $expire);

Note that this actually works more reliably where +1 month can be confusing. For example…

Current Day   | first day of +1 month     | +1 month
---------------------------------------------------------------------------
2015-01-01    | 2015-02-01                | 2015-02-01
2015-01-30    | 2015-02-01                | 2015-03-02  (skips Feb)
2015-01-31    | 2015-02-01                | 2015-03-03  (skips Feb)
2015-03-31    | 2015-04-01                | 2015-05-01  (skips April)
2015-12-31    | 2016-01-01                | 2016-01-31

Answer:

Be careful, because sometimes strtotime("+1 months") can skip month numbers.

Example:

$today = date("Y-m-d"); // 2012-01-30
$next_month = date("Y-m-d", strtotime("$today +1 month"));

If today is January, next month should be February which has 28 or 29 days, but PHP will return March as next month, not February.

Answer:

You can use strtotime() as in Gazler’s example, which is great for this case.

If you need more complicated control use mktime().

$end_date = mktime(date("H"), date("i"), date("s"), date("n") + 1, date("j"), date("Y"));

Answer:

date("Y-m-d",strtotime("last day of +1 month",strtotime($anydate)))

Answer:

Adding my solution here, as this is the thread that comes in google search. This is to get the next date of month, fixing any skips, keeping the next date within next month.

PHP adds current months total number of days to current date, if you do +1 month for example.

So applying +1 month to 30-01-2016 will return 02-03-2016. (Adding 31 days)

For my case, I needed to get 28-02-2016, so as to keep it within next month. In such cases you can use the solution below.

This code will identify if the given date’s day is greater than next month’s total days. If so It will subtract the days smartly and return the date within the month range.

Do note the return value is in timestamp format.

function getExactDateAfterMonths($timestamp, $months){
    $day_current_date            = date('d', $timestamp);
    $first_date_of_current_month = date('01-m-Y', $timestamp);
    // 't' gives last day of month, which is equal to no of days
    $days_in_next_month          = date('t',  strtotime("+".$months." months", strtotime($first_date_of_current_month)));

    $days_to_substract = 0;
    if($day_current_date > $days_in_next_month)
         $days_to_substract = $day_current_date - $days_in_next_month;

    $php_date_after_months   = strtotime("+".$months." months", $timestamp);
    $exact_date_after_months = strtotime("-".$days_to_substract." days", $php_date_after_months);

    return $exact_date_after_months;
}

getExactDateAfterMonths(strtotime('30-01-2016'), 1);
// $php_date_after_months   => 02-03-2016
// $exact_date_after_months => 28-02-2016

Answer:

This function returns any correct number of months positively or negatively. Found in the comment section here:

function addMonthsToTime($numMonths = 1, $timeStamp = null){
    $timeStamp === null and $timeStamp = time();//Default to the present
    $newMonthNumDays =  date('d',strtotime('last day of '.$numMonths.' months', $timeStamp));//Number of days in the new month
    $currentDayOfMonth = date('d',$timeStamp);

    if($currentDayOfMonth > $newMonthNumDays){
      $newTimeStamp = strtotime('-'.($currentDayOfMonth - $newMonthNumDays).' days '.$numMonths.' months', $timeStamp);
    } else {
    $newTimeStamp = strtotime($numMonths.' months', $timeStamp);
    }

    return $newTimeStamp;
}

Answer:

01-Feb-2014

$date = mktime( 0, 0, 0, 2, 1, 2014 );

echo strftime( '%d %B %Y', strtotime( '+1 month', $date ) );

Answer:

I think this is similar to kouton’s answer, but this one just takes in a timeStamp and returns a timestamp SOMEWHERE in the next month. You could use date(“m”, $nextMonthDateN) from there.

function nextMonthTimeStamp($curDateN){ 
   $nextMonthDateN = $curDateN;
   while( date("m", $nextMonthDateN) == date("m", $curDateN) ){
      $nextMonthDateN += 60*60*24*27;
   }
   return $nextMonthDateN; //or return date("m", $nextMonthDateN);
}

Answer:

I know – sort of late. But I was working at the same problem. If a client buys a month of service, he/she expects to end it a month later. Here’s how I solved it:

    $now = time(); 
    $day = date('j',$now);
    $year = date('o',$now);
    $month = date('n',$now);
    $hour = date('G');
    $minute = date('i');
    $month += $count;
    if ($month > 12)        {
            $month -= 12;
            $year++; 
            }
    $work = strtotime($year . "-" . $month . "-01");
    $avail = date('t',$work);
    if ($day > $avail)
            $day = $avail;
    $stamp = strtotime($year . "-" . $month . "-" . $day . " " . $hour . ":" . $minute);

This will calculate the exact day n*count months from now (where count <= 12). If the service started March 31, 2019 and runs for 11 months, it will end on Feb 29, 2020. If it runs for just one month, the end date is Apr 30, 2019.

Answer:

$nextm = date(‘m’, strtotime(‘+1 month’, strtotime(date(‘Y-m-01’))));