Consider this QUERY (DEMO IS HERE)
(SELECT * FROM `titles` where title = 'test\') UNION ALL (SELECT * FROM `titles` where title LIKE 'test\\')
| ID | TITLE | -------------- | 1 | test\ | | 1 | test\ |
Why no extra (\) required for (=) but for (like) additional \\ is required?
Its clear that MySQL escaped the (test\) with (test\\) then using (test\\\\) is logical for LIKE.
CREATE TABLE IF NOT EXISTS `titles` ( `id` int(11) NOT NULL AUTO_INCREMENT, `title` varchar(255) CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=7 ; -- -- Dumping data for table `titles` -- INSERT INTO `titles` (`id`, `title`) VALUES (1, 'test\');
\ functions as an escape character in
LIKE by default.
From the manual for
Because MySQL uses C escape syntax in strings (for example, “\n” to represent a newline character), you must double any “\” that you use in LIKE strings. For example, to search for “\n”, specify it as “\\n”. To search for “\”, specify it as “\\\\”; this is because the backslashes are stripped once by the parser and again when the pattern match is made, leaving a single backslash to be matched against.
You can change this by specifying another escape character, as in:
SELECT * FROM `titles` where title LIKE 'test\' ESCAPE '|'
Actually, all previous answers have been mangled somewhere. As you can see in the link provided by Karoly Horvath, whose significant bit is reproduced by Explosion Pills, the correct way of searching for 1 backslash (\) is to use 4 backslashes at once (\\\\).
By the way, to show above that single backslash I had to use two at once and to show those four I had to use eight.
LIKE accepts two wildchar characters,
To be able to match these characters, escaping can be used:
\_. This also means that if you want to match
\, it has to be escaped as well.
All this is documented in the manual.
For finding a
\ within a text field I had to escape the
\ twice, else the
% at the end was found:
SELECT * FROM `table` where `field` LIKE '%\\%';
If you wanted to remove the (\’) from the database column (Test\’s) and replace it with apostrophy(Test’s) then you can use the following query.
SELECT replace(column_name, "\'", "'") FROM table where column_name LIKE "%\\%";