I’m coding a web site and I have a php fonction called site_nav.php which first define a $list array and than echos it in a json form.
This way, I can get my web site map with ajax.
My problem is that now, I would like to get the $list object in php, without echoing the json object.
My question: Is there a way to include my php file without activation of the echo call which is in it?
Thanks a lot!
ob_start(); include("file.php"); ob_end_clean();
You could use an output buffer to catch the output in a string.
ob_start(); include_once('file.php'); var $output = ob_get_contents(); ob_end_clean();
You can use output buffering to achieve this.
ob_start(); include("myfile.php"); ob_end_clean();
It’s not possible without a hack. You could use output buffering:
<?php ob_start(); echo "foo"; ob_end_clean();
Instead of the echo, you put your include statement there.
You may want to look into output buffering:
Though I suspect the design of your application can be improved so you don’t need this.