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php – laravel-5.4 – error :Creating default object from empty value

Posted by: admin July 12, 2020 Leave a comment

Questions:

I want to store image path in database. My Controller code undervendor\laravel\framework\src\Illuminate\Foundation\Auth\RegistersUsers.php follows:

public function register(Request $request)
{
    $this->validator($request->all())->validate();

    if($request->hasFile('image')) {
    $image_name = $request->file('image')->getClientOriginalName();              
    $image_path = $request->file('image')->store('public'); 
    $user->image = Storage::url($image_name);
    $user->save();
    }

    event(new Registered($user = $this->create($request->all())));

   // $this->guard()->login($user); disable autologin for new users

    return $this->registered($request, $user)
                    ?: redirect($this->redirectPath());
}

I am getting the following error: ErrorException in RegistersUsers.php line 40: Creating default object from empty value enter image description here.

The image is getting saved in public folder but not able to save image path in the user table database. schema of user table
Schema::create('users', function (Blueprint $table) {
$table->increments('user_id');
$table->string('name');
$table->string('image');
$table->rememberToken();
$table->timestamps();

how to proceed to store the image path in the user table in database

How to&Answers:

you haven’t initialized the variable $user so in the controller and before using it you’ve to add $user = new User; assuming that you already have use App\User;

or $user = new \App\User; if you don’t.

Update
if you’re trying to update an existing user record you’ve to initialize the $user variable by selecting based on it’s primary key which should be sent in the request and then doing the initialization like:

$user_id = $request->input('user_id');
$user = User::find($user_id);

Answer:

Use the simple way below:

$user = User::where('id', '=', $id)->first(); // where id is method param from url or request object
$user->save();

This is also easier when updating multiple tables where the ids in the sub-tables have foreign keys and need to be explicitly defined in the update process.

Also $user = User::find($id); normally work where the $id is the primary key of that object table