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php – Returning two values from a function

Posted by: admin April 23, 2020 Leave a comment

Questions:

Is it possible to return two values when calling a function that would output the values?

For example, I have this:

<?php
    function ids($uid = 0, $sid = '')
    {
        $uid = 1;
        $sid = md5(time());

        return $uid;
        return $sid;
    }

    echo ids();
?>

Which will output 1. I want to chose what to ouput, e.g. ids($sid), but it will still output 1.

Is it even possible?

How to&Answers:

You can only return one value. But you can use an array that itself contains the other two values:

return array($uid, $sid);

Then you access the values like:

$ids = ids();
echo $ids[0];  // uid
echo $ids[1];  // sid

You could also use an associative array:

return array('uid' => $uid, 'sid' => $sid);

And accessing it:

$ids = ids();
echo $ids['uid'];
echo $ids['sid'];

Answer:

Return an array or an object if you need to return multiple values. For example:

function foo() {
    return array(3, 'joe');
}

$data = foo();
$id = $data[0];
$username = $data[1];

// or:
list($id, $username) = foo();

Answer:

You can use an array and the list function to get the info easily :

function multi($a,$b) {
   return array($a,$b);
}

list($first,$second) = multi(1,2);

I hope this will help you

Jerome

Answer:

function ids($uid = 0, $sid = '') 
{ 
    $uid = 1; 
    $sid = md5(time()); 

    return array('uid' => $uid,
                 'sid' => $sid
                );     
} 

$t = ids(); 
echo $t['uid'],'<br />';
echo $t['sid'],'<br />';

Answer:

Many possibilities:

// return array
function f() {
    return array($uid, $sid);
}
list($uid, $sid) = f();
$uid;
$sid;

// return object
function f() {
    $obj = new stdClass;
    $obj->uid = $uid;
    $obj->sid = $sid;
    return $obj;
}
$obj->uid;
$obj->sid;

// assign by reference
function f(&$uid, &$sid) {
    $uid = '...';
    $sid = '...';
}
f($uid, $sid);
$uid;
$sid;

Answer:

Pass by reference would be a solution.
This way you:

  • return a value as you normally would

  • and modify the second (the one passed by refference to the function)

An example:

function foo(&$var) // notice the & in front of the parameter passed
{
    $var++;
    return 1;
}

$a=5;
echo foo($a);
// echoes 1, the returned value
echo $a;
// $a is now 6

Answer:

return array('uid' => $uid, 'sid' => $sid);

and then access it like

$dinga = ids();
extract($dinga);

extract will make uid and sid variable. So then you can use $uid and $sid.