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Programmatically scroll to a specific position in an Android ListView

Posted by: admin March 10, 2020 Leave a comment

Questions:

How can I programmatically scroll to a specific position in a ListView?

For example, I have a String[] {A,B,C,D....}, and I need to set the top visible item of the ListView to the index 21 of my String[].

How to&Answers:

For a direct scroll:

getListView().setSelection(21);

For a smooth scroll:

getListView().smoothScrollToPosition(21);

Answer:

For a SmoothScroll with Scroll duration:

getListView().smoothScrollToPositionFromTop(position,offset,duration);

Parameters
position -> Position to scroll to
offset —->Desired distance in pixels of position from the top of the view when scrolling is finished
duration-> Number of milliseconds to use for the scroll

Note: From API 11.

HandlerExploit’s answer was what I was looking for, but My listview is quite lengthy and also with alphabet scroller. Then I found that the same function can take other parameters as well 🙂


Edit:(From AFDs suggestion)

To position the current selection:

int h1 = mListView.getHeight();
int h2 = listViewRow.getHeight();

mListView.smoothScrollToPositionFromTop(position, h1/2 - h2/2, duration);  

Answer:

Put your code in handler as follows,

public void timerDelayRunForScroll(long time) {
        Handler handler = new Handler(); 
        handler.postDelayed(new Runnable() {           
            public void run() {   
                try {
                    lstView.smoothScrollToPosition(YOUR_POSITION);
                } catch (Exception e) {}
            }
        }, time); 
    }

and then call this method like,

timerDelayRunForScroll(100);

CHEERS!!!

Answer:

I have set OnGroupExpandListener and override onGroupExpand() as:

and use setSelectionFromTop() method which
Sets the selected item and positions the selection y pixels from the top edge of the ListView. (If in touch mode, the item will not be selected but it will still be positioned appropriately.) (android docs)

    yourlist.setOnGroupExpandListener (new ExpandableListView.OnGroupExpandListener()
    {

        @Override
        public void onGroupExpand(int groupPosition) {

            expList.setSelectionFromTop(groupPosition, 0);
            //your other code
        }
    });

Answer:

The Listview scroll will be positioned to top by default, but want to scroll if not visible then use this:

if (listView1.getFirstVisiblePosition() > position || listView1.getLastVisiblePosition() < position)
            listView1.setSelection(position);

Answer:

If someone looking for a similar functionality like Gmail app,

The Listview scroll will be positioned to top by default. Thanks for the hint.
amalBit.
Just subtract it. That’s it.

 Handler handler = new Handler();
    handler.postDelayed(new Runnable() {
        @Override
        public void run() {
            int h1 = mDrawerList.getHeight();
            int h2 = header.getHeight();
            mDrawerList.smoothScrollToPosition(h2-h1);
        }
    }, 1000);

Answer:

Handling listView scrolling using UP/ Down using.button

If someone is interested in handling listView one row up/down using button. then.

public View.OnClickListener onChk = new View.OnClickListener() {
             public void onClick(View v) {

                 int index = list.getFirstVisiblePosition();
                 getListView().smoothScrollToPosition(index+1); // For increment. 

}
});

Answer:

If you want to jump directly to the desired position in a listView just use

listView.setSelection(int position);

and if you want to jump smoothly to the desired position in listView just use

listView.smoothScrollToPosition(int position);

Answer:

This is what worked for me. Combination of answers by amalBit & Melbourne Lopes

public void timerDelayRunForScroll(long time) {
    Handler handler = new Handler(); 
    handler.postDelayed(new Runnable() {           
        public void run() {   
            try {
                  int h1 = mListView.getHeight();
                  int h2 = v.getHeight();

                  mListView.smoothScrollToPositionFromTop(YOUR_POSITION, h1/2 - h2/2, 500);  

            } catch (Exception e) {}
        }
    }, time); 
}

and then call this method like:

timerDelayRunForScroll(400);

Answer:

its easy
list-view.set selection(you pos);
or you can save your position with sharedprefrenceand when you start activity
it get preferences and setseletion to that int

Answer:

-If you just want the list to scroll up\dawn to a specific position:

myListView.smoothScrollToPosition(i);

-if you want to get the position of a specific item in myListView:

myListView.getItemAtPosition(i);

-also this myListView.getVerticalScrollbarPosition(i);can helps you.

Good Luck 🙂

Answer:

I found this solution to allow the scroll up and down using two different buttons.

As suggested by @Nepster I implement the scroll programmatically using the getFirstVisiblePosition() and getLastVisiblePosition() to get the current position.

final ListView lwresult = (ListView) findViewById(R.id.rds_rdi_mat_list);
    .....

        if (list.size() > 0) {
            ImageButton bnt = (ImageButton) findViewById(R.id.down_action);
            bnt.setVisibility(View.VISIBLE);
            bnt.setOnClickListener(new OnClickListener() {

                @Override
                public void onClick(View v) {
                    if(lwresult.getLastVisiblePosition()<lwresult.getAdapter().getCount()){
                        lwresult.smoothScrollToPosition(lwresult.getLastVisiblePosition()+5);
                    }else{
                        lwresult.smoothScrollToPosition(lwresult.getAdapter().getCount());

                    }
                }
            });
            bnt = (ImageButton) findViewById(R.id.up_action);
            bnt.setVisibility(View.VISIBLE);

            bnt.setOnClickListener(new OnClickListener() {

                @Override
                public void onClick(View v) {
                    if(lwresult.getFirstVisiblePosition()>0){
                        lwresult.smoothScrollToPosition(lwresult.getFirstVisiblePosition()-5);
                    }else{
                        lwresult.smoothScrollToPosition(0);
                    }

                }
            });
        }