I have the following algorithm to parse a column for integer values:
def getddr(ws):
address = []
col_name = 'C'
start_row = 4
end_row = ws.get_highest_row()+1
range_expr = "{col}{start_row}:{col}{end_row}".format(col=col_name, start_row=start_row, end_row=end_row)
for row in ws.iter_rows(range_string=range_expr):
print row
raw_input("enter to continue")
cell = row[0]
if str(cell.value).isdigit:
address.append(cell.value)
else:
continue
return address
This crashes at cell = row[0] saying “IndexError: tuple index out of range”, and i dont know what this means. I tried printing out row to see what it contained, but all it gives me is an empty set of parentheses. Anyone know what I’m missing?
That is not so easy to say what is the problem you have, because there are no input data that you are trying to process.
But I can explain what is the reason of the error you’ve get, and in which direction you must go. The list row contains 0 elements (row = []), because of that you can not say row[0] — there are no row[0]. The first thing you must change is check, how long is your list, and when if it is long enough make other things:
for row in ws.iter_rows(range_string=range_expr):
print row
raw_input("enter to continue")
if len(row) > 0:
cell = row[0]
if str(cell.value).isdigit:
address.append(cell.value)
else:
continue
That is the first step that you must do anyway.
Tags: parsing, pythonpython
