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# r – How to display this different in Excel?

Questions:

I did some calculations in R and I want to produce it into excel like this

DATA1          DATA2

54.364         2.05

56.532

54.21

41.485

65.8745

54.0546

75.156

but instead is coming like this

DATA1          DATA2

54.364         2.05

56.532         2.05

54.21          2.05

41.485         2.05

65.8745        2.05

54.0546        2.05

75.156         2.05

My function to produce it in excel is

write.xlsx(c(data.frame(DATA1),data.frame(DATA2)))

Although data1 has values of 54.364, 56.532, 54.21, 41.485, 65.8745, 54.0546, 75.156 and data2 2.05

Excel has a rather bizarre “copy down” feature where it copies a function returning a scalar into every cell in the calling range. It appears that this is happening to you here.

One way to work round this is to use Application.Caller at the top of the function that’s called directly. This returns a Range object denoting the calling range. You can then pad your function return values with #N/A. You do this by inserting variant types into your array set to VT_ERROR and the error vales set to xlErrNa. You can use CVErr(xlErrNa) to do that in one step. Padding with #N/A matches what Excel does with oversized calling ranges for functions returning arrays.

Following code can also be used:
(using @akrun’s data in https://stackoverflow.com/questions/25547210/how-to-produce-this-order-in-r)

DATA1 <- c(54.364, 56.532, 54.21, 41.845, 65.8745, 54.0546, 75.156)
DATA2 <- 2.05
DATA3 <- c(2.2, 2.4, 2.32)

outdf = data.frame(data1=numeric(), data2=numeric(), data3=numeric())
for(i in 1:length(DATA1)) outdf[i,]=c(DATA1[i],0,0)
for(i in 1:length(DATA2)) outdf\$data2[i]=DATA2[i]
for(i in 1:length(DATA3)) outdf\$data3[i]=DATA3[i]
outdf
data1 data2 data3
1 54.3640  2.05  2.20
2 56.5320  0.00  2.40
3 54.2100  0.00  2.32
4 41.8450  0.00  0.00
5 65.8745  0.00  0.00
6 54.0546  0.00  0.00
7 75.1560  0.00  0.00

Then you can use outdf with write.xlsx .