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Single, double quotes and sizeof('a') in C/C++

Posted by: admin November 30, 2017 Leave a comment

Questions:

I was looking at the question Single quotes vs. double quotes in C or C++. I couldn’t completely understand the explanation given so I wrote a program:

#include <stdio.h>
int main()
{
  char ch = 'a';
  printf("sizeof(ch) :%d\n", sizeof(ch));
  printf("sizeof(\'a\') :%d\n", sizeof('a'));
  printf("sizeof(\"a\") :%d\n", sizeof("a"));
  printf("sizeof(char) :%d\n", sizeof(char));
  printf("sizeof(int) :%d\n", sizeof(int));
  return 0;
}

I compiled them using both gcc and g++ and these are my outputs:

gcc:

sizeof(ch)   : 1  
sizeof('a')  : 4  
sizeof("a")  : 2  
sizeof(char) : 1  
sizeof(int)  : 4  

g++:

sizeof(ch)   : 1  
sizeof('a')  : 1  
sizeof("a")  : 2  
sizeof(char) : 1  
sizeof(int)  : 4  

The g++ output makes sense to me and I don’t have any doubt regarding that. In gcc, what is the need to have sizeof('a') to be different from sizeof(char)? Is there some actual reason behind it or is it just historical?

Also in C if char and 'a' have different size, does that mean that when we write
char ch = 'a';, we are doing implicit type-conversion?

Answers:

In C, character constants such as 'a' have type int, in C++ it’s char.

Regarding the last question, yes,

char ch = 'a';

causes an implicit conversion of the int to char.

Questions:
Answers:

because there is no char just intgers linked int a character

like a is 62 i guess

if you try printf(“%c”,62); you will see a character