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Trying to get property of non-object in [duplicate]

Posted by: admin December 5, 2017 Leave a comment

Questions:

This question already has an answer here:

Answers:

Check the manual for mysql_fetch_object(). It returns an object, not an array of objects.

I’m guessing you want something like this

$results = mysql_query("SELECT * FROM sidemenu WHERE `menu_id`='".$menu."' ORDER BY `id` ASC LIMIT 1", $con);

$sidemenus = array();
while ($sidemenu = mysql_fetch_object($results)) {
    $sidemenus[] = $sidemenu;
}

Might I suggest you have a look at PDO. PDOStatement::fetchAll(PDO::FETCH_OBJ) does what you assumed mysql_fetch_object() to do

Questions:
Answers:

Your error

Notice: Trying to get property of non-object in C:\wamp\www\phone\pages\init.php on line 22

Your comment

@22 is <?php echo $sidemenu->mname."<br />";?>

$sidemenu is not an object, and you are trying to access one of its properties.

That is the reason for your error.

Questions:
Answers:

$sidemenu is not an object, so you can’t call methods on it. It is probably not being sent to your view, or $sidemenus is empty.

Questions:
Answers:
<?php foreach ($sidemenus->mname as $sidemenu): ?>
<?php echo $sidemenu ."<br />";?>

or

$sidemenus = mysql_fetch_array($results);

then

<?php echo $sidemenu['mname']."<br />";?>

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